document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=551531>Question 551531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary.If one angle measures twice the other. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359754 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359754\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's say the angles are A and B.<BR>\n" );
document.write( "If A and B are supplementary then A+B = 180 degrees.<BR>\n" );
document.write( "If angle A = 2B then:<BR>\n" );
document.write( "A+B = 180 Substitute A = 2B.<BR>\n" );
document.write( "2B+B = 180<BR>\n" );
document.write( "3B = 180<BR>\n" );
document.write( "B = 60 degrees and A = 2(60) = 120 degrees. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );