document.write( "Question 551383: One group of workers can do a job in 8 days. After this group has worked 3 days, another group joins it and together they complete the job in 3 more days. In what time could the second group have done the job alone? Please, thank yoou~ Haappy New Year Tutors and Students! <3 \n" ); document.write( "
Algebra.Com's Answer #359720 by ankor@dixie-net.com(22740)\"\" \"About 
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One group of workers can do a job in 8 days.
\n" ); document.write( "After this group has worked 3 days, another group joins it and together they complete the job in 3 more days.
\n" ); document.write( " In what time could the second group have done the job alone?
\n" ); document.write( ":
\n" ); document.write( "let t = time required by the 2nd group to do the job alone
\n" ); document.write( "let the completed job = 1
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\n" ); document.write( "From the given information, we know the 1st group worked a total of 6 days.
\n" ); document.write( ":
\n" ); document.write( "The shared work equation
\n" ); document.write( "\"6%2F8\" + \"3%2Ft\" = 1
\n" ); document.write( "multiply by 8t, to clear the denominators
\n" ); document.write( "6t + 8(3) = 8t
\n" ); document.write( "24 = 8t - 6t
\n" ); document.write( "24 = 2t
\n" ); document.write( "t = 24/2
\n" ); document.write( "t = 12 days required by the 2nd group alone
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\n" ); document.write( ":
\n" ); document.write( "see if this checks out
\n" ); document.write( "\"6%2F8\" + \"3%2F12\" =
\n" ); document.write( ".75 + .25 = 1
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