document.write( "Question 551302: The supervisor sells 1 type of tea for $11.00 pd and the other for $5.00 pd The supervisor wants to make 70 pds of the $11 tea for $7.00 pd....how much of the $5.00 should be used? \n" ); document.write( "
Algebra.Com's Answer #359715 by Theo(13342)\"\" \"About 
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let x = the number of pounds of the 11 dollars a pound tea.
\n" ); document.write( "let y = the number of pounds of the 5 dollars a pound tea.
\n" ); document.write( "x + y = 70 pounds
\n" ); document.write( "11x + 5y = 7*70 = 490 dollars
\n" ); document.write( "use the first equation to solve for y to get y = 70 - x
\n" ); document.write( "substitute for y in the second equation to get:
\n" ); document.write( "11x + 5(70-x) = 490
\n" ); document.write( "simplify this equation to get:
\n" ); document.write( "11x + 350 - 5x = 490
\n" ); document.write( "combine like terms and subtract 350 from both sides of the equation to get:
\n" ); document.write( "6x = 140
\n" ); document.write( "divide both sides by 6 to get:
\n" ); document.write( "x = 23.3333333
\n" ); document.write( "if x = 23.33333333 then y = 46.66666667 because x + y = 70
\n" ); document.write( "when x = 23.33333333 and y = 46.66666667, the equation of:
\n" ); document.write( "11x + 5y = 490 becomes:
\n" ); document.write( "11*23.33333333 + 5*46.66666667 = 490 which becomes:
\n" ); document.write( "256.66666666 + 233.33333334 = 490.
\n" ); document.write( "numbers check out so the answer is:
\n" ); document.write( "46 and 2/3 pounds of the 5 dollar a pound tea needs to be mixed with 23 and 1/3 pounds of the 11 dollar tea.
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