document.write( "Question 551396: The radiator of a jeep has a capacity of 4 gallons. It is filled with an anti-freeze solution of water and glycol which analyzes 10% glycol. What volume of the mixture must be drawn off and replaced with glycol to obtain a 25% glycol solution? All percentages are by volume. Please thank you~ <3 \n" ); document.write( "

Algebra.Com's Answer #359702 by Earlsdon(6294) $\"\"$ $\"About$

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Think in terms of the amount of glycol in this situation.
\n" ); document.write( "Initially you have 4 gallons of solution that is 10% glycol.
\n" ); document.write( "The amount of glycol is then 4(0.1) = 0.4 gallons.
\n" ); document.write( "You want to remove some of this solution, let's call it x gallons. So we now have:
\n" ); document.write( "4(0.1)-x(0.1) of glycol.
\n" ); document.write( "Then you want to replace the removed amount of the 10% solution with the same amount of pure (100%) glycol or x(1), so we have:
\n" ); document.write( "4(0.1)-x(0.1)+x and this is to equal 4 gallons of 25% glycol solution which is 4(0.25) glycol.
\n" ); document.write( "So here's the equation to solve for x.
\n" ); document.write( "4(0.1)-x(0.1)+x = 4(0.25) Simplify.
\n" ); document.write( "0.4+0.9x = 1
\n" ); document.write( "0.9x = 0.6
\n" ); document.write( "x = 0.67 gallons.
\n" ); document.write( "You must draw off $\"2%2F3\"$ of a gallon of the 10% solution and replace it with $\"2%2F3\"$ of a gallon of pure glycol. \n" ); document.write( "

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