document.write( "Question 551373: if the length of the rectangle is one foot less than the width and the area is 12ft squared ,find the dimensions.
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Algebra.Com's Answer #359694 by nerdybill(7384)\"\" \"About 
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if the length of the rectangle is one foot less than the width and the area is 12ft squared ,find the dimensions.
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\n" ); document.write( "Let w = width
\n" ); document.write( "then
\n" ); document.write( "w-1 = length
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\n" ); document.write( "w(w-1) = 12
\n" ); document.write( "w^2-w = 12
\n" ); document.write( "w^2-w-12=0
\n" ); document.write( "factoring:
\n" ); document.write( "(w+3)(w-4) = 0
\n" ); document.write( "w = {-3,4}
\n" ); document.write( "throw out the -3 leaving:
\n" ); document.write( "w = 4 feet (width)
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\n" ); document.write( "Length:
\n" ); document.write( "w-1 = 4-1 = 3 feet (length)
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\n" ); document.write( "solution:
\n" ); document.write( "4 feet by 3 feet \n" ); document.write( "
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