document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=551366>Question 551366</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Divide Rs 1,260 among A,B and C so that the ratio between the shares of A and B is 2:3 and the ratio between the shares of B and C is 4:5.pls.. give me the solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359680 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359680\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The problem gives the following:<P><BR>\n" );
document.write( "A+B+C=1260<BR>\n" );
document.write( "A/B = 2/3 cross multiply 3A = 2B and B = 3/2 * A<BR>\n" );
document.write( "B/C = 4/5 cross multiply 5B = 4C and C = 5/4 * B<P><BR>\n" );
document.write( "Solve the first equation for A by substituting in B and C in terms of A.<P><BR>\n" );
document.write( "B = 3/2 * A and C = 5/4 * B = 5/4 * 3/2 * A = 15/8 * A<P><BR>\n" );
document.write( "A + (3/2)A + (15/8)A = 1260<BR>\n" );
document.write( "(8A + 12A + 15A)/8 = 1260<BR>\n" );
document.write( "35A = 10080<BR>\n" );
document.write( "A=288<P><BR>\n" );
document.write( "B = 3/2 * A = 3/2 * 288 = 432<BR>\n" );
document.write( "C = 5/4 * B = 5/4 * 432 = 540<BR>\n" );
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