document.write( "Question 551349: ~Working together a man and woman can do the job in 8 hours. if either had to do it alone, it would take a woman 2 hours longer than a man. How long would it take either person working alone?
\n" ); document.write( "~A reservoir can be filled by one pipe in 6 hours and by another in 8 hours. It can be emptied by a third pipe in 10 hours. Starting empty, how long will it take to fill the reservoir if all pipes are open?\r
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Algebra.Com's Answer #359671 by mananth(16946)\"\" \"About 
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let Man take x hours to complete the job alone
\n" ); document.write( "so he does 1/x of the job in 1 hour\r
\n" ); document.write( "\n" ); document.write( "woman takes 1/(x+2) hours to do the same job
\n" ); document.write( "so she does 1/(x+2) of the job in 1 hour\r
\n" ); document.write( "\n" ); document.write( "Together they can do 1/x + 1/(x+2) of the job in 1 hour
\n" ); document.write( "add up both
\n" ); document.write( "=(2x+2)/x(x+2) \r
\n" ); document.write( "\n" ); document.write( "so they take x(x+2)/(2x+2) hours\r
\n" ); document.write( "\n" ); document.write( "x(x+2)/(2x+2)= 10
\n" ); document.write( "x(x+2)=10(2x+2)
\n" ); document.write( "x^2+2x=20x+20
\n" ); document.write( "x^2-18x-20=0
\n" ); document.write( "x^2-20x+2x-20=0
\n" ); document.write( "x(x-20)+2(x-20)=0
\n" ); document.write( "(x-20)(x+2)=0
\n" ); document.write( "Take the positive value
\n" ); document.write( "x= 20 \r
\n" ); document.write( "\n" ); document.write( "Man takes 20 hours
\n" ); document.write( "Woman takes 20 +2 = 22 hours
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\n" ); document.write( "\n" ); document.write( "1/6 +1/8 - 1/10 is the job done in 1 hour ( filling the pool)
\n" ); document.write( "7/24 - 1/10
\n" ); document.write( "Addup
\n" ); document.write( "(70-24)/240
\n" ); document.write( "46/240 of the job is done in 1 hour
\n" ); document.write( "so it will take 240/46 hours = 5.2 hours\r
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