document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=551350>Question 551350</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ~ Two automobiles start out from two points kilometers apart and travel toward each other. The automobile from the east travels at 10 kph faster than the automobile from the west. If they meet after 5 hours, what is the average speed of each automobile?<BR>\n" );
document.write( "~One man is five times as old as his brother. Fifteen years later, he will be twice as old. How old are the two men now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359670 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359670\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Problem 1 how man km apart\r<BR>\n" );
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document.write( "brother's age =x<BR>\n" );
document.write( "man's age = 5x\r<BR>\n" );
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document.write( "after 15 years<BR>\n" );
document.write( "brother's age = x+15<BR>\n" );
document.write( "Man's age = 5x+15\r<BR>\n" );
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document.write( "5x+15= 2(x+15)<BR>\n" );
document.write( "5x+15=2x+30<BR>\n" );
document.write( "5x-2x=15<BR>\n" );
document.write( "3x=15<BR>\n" );
document.write( "x=5 brother's age<BR>\n" );
document.write( "Man's age = 5x = 5*5 = 25 years\r<BR>\n" );
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document.write( "HAPPY NEW YEAR\r<BR>\n" );
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document.write( " </SPAN>\n" );
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