document.write( "Question 551305: how many gallons of 25% sugar content kool aid and 40% sugar content kool aid need to be mixed in order to make 50 gallons of 30% sugar content kool aid? \n" ); document.write( "
Algebra.Com's Answer #359636 by chelcilovesmj1(3)\"\" \"About 
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Let
\n" ); document.write( "A= the amount of 25% kool aid
\n" ); document.write( "B= the amount of 40% kool aid\r
\n" ); document.write( "\n" ); document.write( "2 equations are needed\r
\n" ); document.write( "\n" ); document.write( "1.) A+B = 50 gallons of kool aid
\n" ); document.write( "2.) .25(A) + .40(B) = .30(50)\r
\n" ); document.write( "\n" ); document.write( "1.)rewrite 1st eqaution as such... B = 50-A\r
\n" ); document.write( "\n" ); document.write( "2.)substitute newly written equation as such...
\n" ); document.write( " .25(A) + .40(50-A) = 15
\n" ); document.write( " .25(A) - .40(A) + 20 = 15
\n" ); document.write( " -.15A = -5
\n" ); document.write( " A = (approx) 33.3 gallons
\n" ); document.write( "3.) use 1st equation to solve for B
\n" ); document.write( " 33.3 + B = 50
\n" ); document.write( " B = 16.7 gallons\r
\n" ); document.write( "\n" ); document.write( "4.) Final Answer
\n" ); document.write( " A = 33.3 gallons, B = 16.7 gallons\r
\n" ); document.write( "\n" ); document.write( "hope this helps :)\r
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