document.write( "Question 551296: One number is five more than 3 times a second number. If ten is added to -2 times the first number, the result is 30. Find each of the numbers. Please help me!!!!!!! \n" ); document.write( "
Algebra.Com's Answer #359635 by ankor@dixie-net.com(22740)\"\" \"About 
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let a = a number
\n" ); document.write( "let b = a second number
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\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "\"One number is five more than 3 times a second number.\"
\n" ); document.write( "a = 3b + 5
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\n" ); document.write( " \"If ten is added to -2 times the first number, the result is 30.\"
\n" ); document.write( "-2a + 10 = 30
\n" ); document.write( "-2a = 30 - 10
\n" ); document.write( "-2a = 20
\n" ); document.write( "a = \"20%2F%28-2%29\"
\n" ); document.write( "a = -10
\n" ); document.write( ":
\n" ); document.write( "Replace a with -10 on the 1st equation
\n" ); document.write( "-10 = 3b + 5
\n" ); document.write( "-10 - 5 = 3b
\n" ); document.write( "3b = -15
\n" ); document.write( "b = \"%28-15%29%2F3\"
\n" ); document.write( "b = -5
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\n" ); document.write( "You can check these solutions in both statements\r
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