document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=550121>Question 550121</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If A + B =1, B + C = 2, C + D = 3, ... X + Y = 25, Y + Z = 26, find A - Z </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359628 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359628\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose we take the first equation, subtract the second equation, add the third, subtract the fourth, etc...in other words,\r<BR>\n" );
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document.write( "(A+B) - (B+C) + (C+D) - ... -(Y+Z).\r<BR>\n" );
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document.write( "This sum telescopes to A-Z, so we have A-Z = 1-2+3-4+...-26 = -13. </SPAN>\n" );
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