document.write( "Question 551294: Mrs. John is five times as old as her son. Three years ago she was eight times as old as her son was then. Find each of their ages. Please help me solve this!!! \n" ); document.write( "
Algebra.Com's Answer #359592 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Mrs. John is five times as old as her son. Three years ago she was eight times as old as her son was then. Find each of their ages. Please help me solve this!!! \n" ); document.write( "** \n" ); document.write( "At present: \n" ); document.write( "let x=son's age \n" ); document.write( "5x=mother's age \n" ); document.write( ".. \n" ); document.write( "3 years ago: \n" ); document.write( "x-3=son'age \n" ); document.write( "5x-3=mother's age \n" ); document.write( ".. \n" ); document.write( "5x-3=8(x-3) (mother 8 times as old as her son 3 years ago) \n" ); document.write( "5x-3=8x-24 \n" ); document.write( "3x=21 \n" ); document.write( "x=7 \n" ); document.write( "5x=35 \n" ); document.write( "ans: \n" ); document.write( "son's present age=7 \n" ); document.write( "mother's presentage=35 \n" ); document.write( " |