document.write( "Question 53662: PLEASE HELP SOLVE.\r
\n" ); document.write( "\n" ); document.write( "MULDER LEAVES WASHINGTON AT 8:30AM AND AVERAGES 65MPH. HIS PARTNER, SCULLY, LEAVES AT 9:00AM FOLLOWING THE SAME PATH AND AVERAGING 68MPH. AT WHAT TIME WILL SCULLY CATCH UP WITH MULDER. \n" ); document.write( "
Algebra.Com's Answer #35957 by stanbon(75887)\"\" \"About 
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MULDER LEAVES WASHINGTON AT 8:30AM AND AVERAGES 65MPH. HIS PARTNER, SCULLY, LEAVES AT 9:00AM FOLLOWING THE SAME PATH AND AVERAGING 68MPH. AT WHAT TIME WILL SCULLY CATCH UP WITH MULDER.
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\n" ); document.write( "Mulder DATA:
\n" ); document.write( "rate=65 mph ; time= x hrs. ; distance= rt=65x miles
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\n" ); document.write( "Scully DATA:
\n" ); document.write( "rate=68 mph ; time= x-(1/2)=(2x-1)/2 hrs ;
\n" ); document.write( "distance= rt= 68(2x-1)/2= 34(2x-1)=68x-34 miles
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\n" ); document.write( "EQUATION:
\n" ); document.write( "distance = distance
\n" ); document.write( "65x=68x-34
\n" ); document.write( "3x=34
\n" ); document.write( "x=11 1/4 hrs or 11hr 15 min
\n" ); document.write( "The time will be 8:30AM + 11hr 15 min
\n" ); document.write( "I'll let you figure that out.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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