document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=551216>Question 551216</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At what rate must motorist A travel to overtake motorist B who is traveling at a rate 20 mi/hr slower if A starts two hours after B and wishes to overtake B in 4hours. Please thank you <3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359541 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359541\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let speed of B be x mph<BR>\n" );
document.write( "in 2 hours before A starts B  has already traveled  2x miles\r<BR>\n" );
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document.write( "So the difference between A & B when B starts is 2x miles ( d= rt)<BR>\n" );
document.write( "A's rate is 20 km/h more than B's rate . <BR>\n" );
document.write( "catchup speed = 20 mph<BR>\n" );
document.write( "Catch up distance is 2x miles<BR>\n" );
document.write( "t=d/r<BR>\n" );
document.write( "A catches up in 4 hours\r<BR>\n" );
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document.write( "2x/20=4<BR>\n" );
document.write( "2x=80<BR>\n" );
document.write( "x=40\r<BR>\n" );
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document.write( "speed of B is 40 mph<BR>\n" );
document.write( "speed of A = 60 mph<BR>\n" );
document.write( " </SPAN>\n" );
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