document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=551193>Question 551193</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a housewife wishes to mix coffee beans worth Php60 and Php85 a kilogram to obtain 50 kilogram to obtain 50 kilograms of coffee beans worth 70 a kilogram. How many kilogram of each should she use?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359537 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> price		----------------			quantity								<BR>\n" );
document.write( "Cofee beans type I60	----------------xlb							<BR>\n" );
document.write( "coffee beans type II	85----------------50-x	lb							<BR>\n" );
document.write( "Mixture	70.00	----------------50										<BR>\n" );
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document.write( "60x+85(50-x)=70	*50	<BR>\n" );
document.write( "60x+4250-85x=3500			<BR>\n" );
document.write( "60x-85x	=3500-4250			<BR>\n" );
document.write( "-25x	=-750								<BR>\n" );
document.write( "/	-25												<BR>\n" );
document.write( "x=30	lb	Php60.00	Coffee beans type I	<BR>\n" );
document.write( "20		lb Php85.00	coffee beans type II	<BR>\n" );
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