document.write( "Question 551173: For an annual fee of $30, you can join a movie club that will allow you to purchase tickets for $5.50 each at your local theater. The regular price of a ticket is $8. Write and solve an equation to determine how many movie tickets you will have to buy through the movie club for the cost to equal that of buying regularly priced tickets. \n" ); document.write( "
Algebra.Com's Answer #359525 by TutorDelphia(193)\"\" \"About 
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So for the annual fee we have 30 plus the number of movies you see (which we'll call x) times 5.50. On the other hand we just have 8 times the numbers of movies you see (again, we'll call that x)\r
\n" ); document.write( "\n" ); document.write( "Set them equal to each other and solve
\n" ); document.write( "\"30%2B5.5%2Ax=8%2Ax\"
\n" ); document.write( "Subtract 5.5 from both sides
\n" ); document.write( "30=2.5x
\n" ); document.write( "Divide both sides by 2.5
\n" ); document.write( "x=12
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