document.write( "Question 551087: Find three consecutive positive odd integers such that the product of the first and the third is 4 less than 7. Times the second \n" ); document.write( "
Algebra.Com's Answer #359499 by ankor@dixie-net.com(22740)\"\" \"About 
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Find three consecutive positive odd integers such that the product of the first and the third is 4 less than 7. Times the second
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\n" ); document.write( "\"Find three consecutive positive odd integers\"
\n" ); document.write( "x, (x+2), (x+4)
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\n" ); document.write( " such that the product of the first and the third is 4 less than 7. Times the second
\n" ); document.write( "x(x+4) = 7(x+2) - 4
\n" ); document.write( "x^2 + 4x = 7x + 14 - 4
\n" ); document.write( "x^2 + 4x = 7x + 10
\n" ); document.write( "Combine like terms on the left
\n" ); document.write( "x^2 + 4x - 7x - 10 = 0
\n" ); document.write( "x^2 - 3x - 10 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x-5)(x+2) = 0
\n" ); document.write( "two solutions
\n" ); document.write( "x = 5, the positive odd integer, so x=5 is the only solution
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\n" ); document.write( "the three integers, 5, 7, 9
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\n" ); document.write( "see if that works in the statement:
\n" ); document.write( "\"Find three consecutive positive odd integers such that the product of the first and the third is 4 less than 7. Times the second\"
\n" ); document.write( "5*9 = 7(7) - 4
\n" ); document.write( "45 = 49 - 4; confirms our solution \n" ); document.write( "
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