document.write( "Question 551068: 2^-1+9^1/2/9
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document.write( "1/2 +2/9
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document.write( "1/2+3/9= 1/2+3=1/2+6/2\r
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document.write( "32^-2/5+6^0
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document.write( "2^-2+1
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document.write( "(2)^-2+1= 1/2^2+1=1/4+1=2/4 \r
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document.write( "I seem to be running into some problems with these two questions. Can someone help and evaluate my work
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document.write( "thanks \n" );
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Algebra.Com's Answer #359494 by mathstutor458(57)![]() ![]() ![]() You can put this solution on YOUR website! 1)2^-1+9^1/2/9 \n" ); document.write( "1/2 +9/2/9 \n" ); document.write( "1/2+81/2= \n" ); document.write( " (1+81)/2=82/2=41\r \n" ); document.write( "\n" ); document.write( "formula :- a/b/c=ac/b\r \n" ); document.write( "\n" ); document.write( "note:- \n" ); document.write( "In the second step you did wrong,correct that now \n" ); document.write( "According to your caluculation,In the third step you wrote3/9 instead of 2/9 and after that caluculaton part is correct.But the correct answer for your problem is 41.\r \n" ); document.write( "\n" ); document.write( "2)32^-2/5+6^0 \n" ); document.write( "=1/32^2/5 + 1 \n" ); document.write( "=5/32^2+1 \n" ); document.write( "=5/1024 + 1 \n" ); document.write( "=0.004+1 = 1.004\r \n" ); document.write( "\n" ); document.write( "note:- \n" ); document.write( "32=2^5 \n" ); document.write( "you can not cancell out the power value with the denominator value. \n" ); document.write( "and 1/4+1=5/4 not 2/4\r \n" ); document.write( "\n" ); document.write( "you have to see each and every symbol and values carefully otherwise you wont get correct answers.hope you will not repeat the mistakes again.All the Best. \n" ); document.write( " \n" ); document.write( " |