document.write( "Question 551160: A certain two digit number is 13 more than 9 times the tens digit. The original number is 4 less than twice the number formed by interchanging the digits. Find the original number. Please help me!!!!!! \n" ); document.write( "

Algebra.Com's Answer #359471 by lwsshak3(11628) $\"\"$ $\"About$

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A certain two digit number is 13 more than 9 times the tens digit. The original number is 4 less than twice the number formed by interchanging the digits. Find the original number.
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\n" ); document.write( "let t=ten's digit
\n" ); document.write( "let u=unit's digit
\n" ); document.write( "original number=10t+u
\n" ); document.write( "interchanged number=10u+t
\n" ); document.write( "..
\n" ); document.write( "10t+u=9t+13 (original number is 13 more than 9 times the tens digit)
\n" ); document.write( "10t+u=2(10u+t)-4 (original number is 4 less than twice the interchanged number)
\n" ); document.write( "..
\n" ); document.write( "t+u=13
\n" ); document.write( "10t+u=20u+2t-4
\n" ); document.write( "..
\n" ); document.write( "t+u=13
\n" ); document.write( "8t-19u=-4
\n" ); document.write( "..
\n" ); document.write( "8t+8u=104
\n" ); document.write( "8t-19u=-4
\n" ); document.write( "27u=108
\n" ); document.write( "u=4
\n" ); document.write( "t=13-u=9
\n" ); document.write( "original number=94 \n" ); document.write( "

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