document.write( "Question 551085: for part (a) find the sum of the first n terms of the arithmetic series. for part (b) find n for the given sum Sn.\r
\n" ); document.write( "\n" ); document.write( "45. 3+8+13+18+23+...
\n" ); document.write( "a. n=20
\n" ); document.write( "b. Sn=366\r
\n" ); document.write( "\n" ); document.write( "46. 50+42+34+26+18+...
\n" ); document.write( "a. n=40
\n" ); document.write( "b. Sn=182\r
\n" ); document.write( "\n" ); document.write( "47. -10+(-5)+0+5+10+...
\n" ); document.write( "a. n=19
\n" ); document.write( "b. Sn=375\r
\n" ); document.write( "\n" ); document.write( "48. 34+31+28+25+22+...
\n" ); document.write( "a. n=32
\n" ); document.write( "b. Sn=-12\r
\n" ); document.write( "\n" ); document.write( "49. 2+9+16+23+30+...
\n" ); document.write( "a. n=68
\n" ); document.write( "b. Sn=1661\r
\n" ); document.write( "\n" ); document.write( "50. 2+16+30+44+58+...
\n" ); document.write( "a. n=24
\n" ); document.write( "b. Sn=2178\r
\n" ); document.write( "\n" ); document.write( "please show your work also so i know how to do it,
\n" ); document.write( "thank you for ur help and happy new year!
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Algebra.Com's Answer #359427 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
My best guess is that your textbook or class notes tell you that the nth term of an arithmetic sequence, \"a%5Bn%5D\", can be calculated based on the first term, \"a%5B1%5D\", and the common difference, \"d\", as
\n" ); document.write( "\"a%5Bn%5D=a%5B1%5D%2B%28n-1%29%2Ad\".
\n" ); document.write( "Then they must have told you that the sum of the first n terms can be calculated as
\n" ); document.write( "\"S%5Bn%5D=n%2A%28a%5Bn%5D%2Ba%5B1%5D%29%2F2\" or
\n" ); document.write( "\"S%5Bn%5D=n%2Aa%5B1%5D%2Bn%28n-1%29%2Ad%2F2\"
\n" ); document.write( "SOLUTIONS FOR THE FIRST TWO PROBLEMS
\n" ); document.write( "45. 3+8+13+18+23+...
\n" ); document.write( "\"a%5B1%5D=3\" and the common difference is
\n" ); document.write( "\"d=8-3=5\"
\n" ); document.write( "a. n=20 Since you are not given \"a%5B20%5D\", use the second formula
\n" ); document.write( "\"S%5B20%5D=20%2A3%2B20%2820-1%29%2A5%2F2=60%2B20%2A19%2A5%2F2=60%2B950=1010\"
\n" ); document.write( "b. Sn=366 I don't think I ever did this kind of problem.
\n" ); document.write( "I suppose they could expect you to use a guess and check strategy, and you could try n=10, and figure out that the answer is between 10 and 20.
\n" ); document.write( "Otherwise, it gets complicated, but here it goes:
\n" ); document.write( "With \"S%5Bn%5D=n%2Aa%5B1%5D%2Bn%28n-1%29%2Ad%2F2\" plus \"S%5Bn%5D=366\" for this sequence, it means
\n" ); document.write( "\"366=n%2A3%2Bn%28n-1%29%2A5%2F2\", and multiplying both sides times 2
\n" ); document.write( "\"732=6n%2Bn%28n-1%29%2A5\" --> \"732=6n%2B%28n%5E2-n%29%2A5\" --> \"732=6n%2B5n%5E2-5n\" --> \"5n%5E2%2Bn-732=0\"
\n" ); document.write( "Applying the quadratic formula:
\n" ); document.write( "
\n" ); document.write( "That gives us \"n=12\", our answer.
\n" ); document.write( "We disregard the other solution because it's negative, and we were looking for a positive integer for \"n\".
\n" ); document.write( "46. 50+42+34+26+18+...
\n" ); document.write( "has \"a%5B1%5D=50\" and \"d=42-50=-8\".
\n" ); document.write( "That means \"a%5B7%5D=a%5B1%5D%2B%287-1%29%2A%28-8%29=50-48=2\", and \"a%5B8%5D=a%5B7%5D-8=-6\", with all the terms after that being negative.
\n" ); document.write( "What's more the sum of the positive terms (the first 7 terms) is
\n" ); document.write( "\"S%5B7%5D=7%2A%28a%5B7%5D%2Ba%5B1%5D%29%2F2=7%2A%282%2B50%29%2F2=7%2A52%2F2=182\", which answers part b by lucky guess.
\n" ); document.write( "a. n=40
\n" ); document.write( "
\n" ); document.write( "b. Sn=182 We answered it by guess above, but if we need to solve quadratic equations again:
\n" ); document.write( "\"S%5Bn%5D=n%2Aa%5B1%5D%2Bn%28n-1%29%2Ad%2F2\", so \"182=n%2A50%2Bn%28n-1%29%2A%28-8%29%2F2\"
\n" ); document.write( "So, \"182=50n-4n%5E2%2B4n\" --> \"182=50n-4n%5E2%2B4n\" --> \"182=54n-4n%5E2\" --> \"4n%5E2-54n%2B182=0\" --> \"2n%5E2-27n%2B91=0\"
\n" ); document.write( "If you are good at factoring you see that \"2n%5E2-27n%2B91=%282n-13%29%28n-7%29\" to find the solutions to the equation. Otherwise, you apply the quadratic formula. Either way, you find the answer to part b \"n=7\",
\n" ); document.write( "and another solution to the equation, \"13%2F2\", that we discard because it's not a positive integer.
\n" ); document.write( "FOR THE REST
\n" ); document.write( "I hope you know how to do it now. I also hope that guess and check is an accepted and viable alternative to find the answer to part b.
\n" ); document.write( "Here are the answers I calculated for problems 47-50
\n" ); document.write( "47. -10+(-5)+0+5+10+...
\n" ); document.write( "a. n=19 \"S%5B19%5D=665\"
\n" ); document.write( "b. Sn=375 \"n=15\" \"S%5B15%5D=375\"
\n" ); document.write( "48. 34+31+28+25+22+...
\n" ); document.write( "a. n=32 \"S%5B32%5D=-400\"
\n" ); document.write( "b. Sn=-12 \"n=24\" \"S%5B24%5D=-12\"
\n" ); document.write( "49. 2+9+16+23+30+...
\n" ); document.write( "a. n=68 \"S%5B68%5D=16082\"
\n" ); document.write( "b. Sn=1661 \"n=22\" \"S%5B22%5D=1661\"
\n" ); document.write( "50. 2+16+30+44+58+...
\n" ); document.write( "a. n=24 \"S%5B32%5D=3912\"
\n" ); document.write( "b. Sn=2178 \"n=18\" \"S%5B18%5D=2178\"
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