document.write( "Question 6611: Dear Sir/Madam,
\n" ); document.write( "I am confronted with the following problem:\r
\n" ); document.write( "\n" ); document.write( "\"A box with an open top is to be constructed by cutting 3-in squares from the corners of a rectangular sheet of tin, whose length is twice its width, and then folding up the sides. What size sheet of tin will produce a box having a volume of 60 cubic inches?\"\r
\n" ); document.write( "\n" ); document.write( "I did the following:\r
\n" ); document.write( "\n" ); document.write( "1) Volume = l * w * h
\n" ); document.write( "l = 2w
\n" ); document.write( "h = 3
\n" ); document.write( "2) 60 = 2w * w * 3
\n" ); document.write( "3) 6w^2 = 60
\n" ); document.write( "4) w^2 = 10
\n" ); document.write( "5) w = \"+sqrt%2810%29+\"\r
\n" ); document.write( "\n" ); document.write( "But that is not correct. The right answer for the width is 8 inches. What did I do wrong?
\n" ); document.write( "Thanks in advance.
\n" ); document.write( "Regards,
\n" ); document.write( "-Mike
\n" ); document.write( "

Algebra.Com's Answer #3594 by prince_abubu(198)\"\" \"About 
You can put this solution on YOUR website!
Alright. We're cool with V = l * w * h, right, and we know that h = 3 and the volume is 60 in^2. So far we've got\r
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\n" ); document.write( "\n" ); document.write( "\"+60+=+l+%2A+w+%2A+3+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The trick is with the L and the W. You were right when you said that L = 2W. The length of the original sheet is twice the width of the original sheet BEFORE chopping of 3-inch by 3-inch squares on all four corners. When you chop off square corners, the actual length and width of the resulting folded box will definitely be shorter than the original L and W you started with.\r
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\n" ); document.write( "\n" ); document.write( "Let's take the width. We decided to call it w. Now, when we cut off 3 inches from all 4 corners, that would actually chop 6 inches off the width. So the width of your box will have to be w - 6.\r
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\n" ); document.write( "\n" ); document.write( "We know that the length = 2w BEFORE cutting off squares. Like the width, 3 inches were also chopped off the length from BOTH sides, making the actual length (of your box) 6 inches shorter. So the length of the box will be 2w - 6.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let's now plug in the box's width and length:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"+60+=+%282w+-+6%29%28w+-+6%29%283%29+\" <----- We'll solve for the width eventually.\r
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\n" ); document.write( "\n" ); document.write( "\"+20+=+%282w+-+6%29%28w+-+6%29+\" <----- Divided both sides by 3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"+20+=+2w%5E2+-+18x+%2B+36+\" <----- Performed \"FOIL\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"+0+=+2w%5E2+-+18x+%2B+16+\" <----- Subtract 20 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"+0+=+w%5E2+-+9x+%2B+8+\" <---- Divide both sides by 2\r
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\n" ); document.write( "\n" ); document.write( "\"+0+=+%28w+-+8%29%28w+-+1%29+\" <---- \"UnFOILED\" or factored\r
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\n" ); document.write( "\n" ); document.write( "Just by looking at the above equation, the width is either 8 or 1. We'll have to throw out the 1 because that measure for the width won't work if you'll have to chop 6 inches off it. The 8 would, though. If 8 is the width, and the length is twice the width, then the length is 16. So you've got a sheet that was 16\" x 8\".
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