document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=551097>Question 551097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three arithmetic means between -2 and 12. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359394 by </B><A HREF=/tutors/aboutme.mpl?userid=mathstutor458><B>mathstutor458(57)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathstutor458><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359394\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first number = -2<BR>\n" );
document.write( "fifth number = 12<BR>\n" );
document.write( "because we need to find three arithmaetic means between -2 and 12.so, totally we get 5 numbers.<BR>\n" );
document.write( "this is a arithmatic series,numbers must be -2,-2+d,-2+2d,-2+3d,-2+4d<BR>\n" );
document.write( "-2+4d must be equal to 12 because it is fifth number<BR>\n" );
document.write( "-2+4d=12<BR>\n" );
document.write( "4d=12+2=14<BR>\n" );
document.write( "d=14/4=7/2=3.5\r<BR>\n" );
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document.write( "second term = -2+d=-2 + 3.5 = 1.5<BR>\n" );
document.write( "third term = -2+2d = -2+2*3.5= -2+7=5<BR>\n" );
document.write( "fourth term= -2+3d = -2+3*3.5 = -2+10.5=8.5\r<BR>\n" );
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document.write( "Therefore the series is -2,1.5,5,8.5,12 </SPAN>\n" );
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