document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=551095>Question 551095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify<BR>\n" );
document.write( "                 -x^2y^2/x^1/2y^0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359390 by </B><A HREF=/tutors/aboutme.mpl?userid=mathstutor458><B>mathstutor458(57)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathstutor458><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359390\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -x^2y^2/x^1/2y^0 = (-x^2y^2/x^1)(2Y^0)  (since,c/a/b=bc/a)<BR>\n" );
document.write( "                 =(-x^2y^2/x)(2*1)      (since a^1=a,a^0=1)<BR>\n" );
document.write( "                 =2*(-x^(2-1)*y^2)      (since a^p/a^q = a^(p-q))<BR>\n" );
document.write( "                 =-2*(x^1*y^2)<BR>\n" );
document.write( "                 =-2xy^2   --------->answer </SPAN>\n" );
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