document.write( "Question 551086: find the sum of the series\r
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\n" ); document.write( "\n" ); document.write( "please show your work because i don't know how to do these. Also on 51 the answer is 1110 but how? so work on each of the problems would be very liked. \r
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\n" ); document.write( "\n" ); document.write( "51. 20 on top of symbol, i=1 on bottom,(3+5i) on right
\n" ); document.write( "52. 34 on top, i=1 on bottom,(1+8i) on right
\n" ); document.write( "53. 15 on top, i=1 on bottom, (-10-3i) on right
\n" ); document.write( "54. 22 on top, i=1 on bottom, (6-3/4i) on right
\n" ); document.write( "55. 45 on top, i=1 on bottom, (11+4i) on right
\n" ); document.write( "56. 18 on top, i=1 on bottom, (8.1+4.4i) on right
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Algebra.Com's Answer #359373 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "The trick is to use the distributive principle.  Then use the \r\n" );
document.write( "special formulas:\r\n" );
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document.write( "1. You can distribute ∑ over a sum or difference of terms.\r\n" );
document.write( "2. You can take out a constant in front of the ∑.\r\n" );
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document.write( "I'll just do this one and you can easily do the rest.\r\n" );
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\n" ); document.write( "51. 20 on top of symbol, i=1 on bottom,(3+5i) on right.
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document.write( "\"sum%28%283%2B5%2Ai%29%2Ci=1%2C20%29\"\r\n" );
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document.write( "First distribute the ∑ over the sum like this:\r\n" );
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document.write( "\"sum%28%283%29%2Ci=1%2C20%29\" + \"sum%28%285%2Ai%29%2Ci=1%2C20%29\"\r\n" );
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document.write( "Write the 3 as 3·1\r\n" );
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document.write( "\"sum%28%283%2A1%29%2Ci=1%2C20%29\" + \"sum%28%285%2Ai%29%2Ci=1%2C20%29\"\r\n" );
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document.write( "Now you can take the constant 3 out in front of the first \r\n" );
document.write( "summation and take the constant 5 out in front of the second\r\n" );
document.write( "summation, like this:\r\n" );
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document.write( "\"3%2Asum%28%281%29%2Ci=1%2C20%29\" + \"5%2Asum%28%28i%29%2Ci=1%2C20%29\"\r\n" );
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document.write( "Now you can use the special formulas:\r\n" );
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document.write( "\"3%2A20\" + \"5%2Aexpr%28%28%2820%29%2820%2B1%29%29%2F2%29\" = \"60\" + \"5%2Aexpr%28%28%2820%29%2821%29%29%2F2%29\" = 60 + 1050 = 1110.\r\n" );
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document.write( "Now you can do all of them by using the distributive principle first\r\n" );
document.write( "and then using the special formulas.\r\n" );
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document.write( "Edwin
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