document.write( "Question 551039: if the number of dimes are 4 less than 5 times the quarter find how many of each type does he have
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document.write( " and the total is $1.85 \n" );
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Algebra.Com's Answer #359341 by oberobic(2304) ![]() You can put this solution on YOUR website! d = number of dimes \n" ); document.write( "10d = value of dimes in cents \n" ); document.write( "q = number of quarters \n" ); document.write( "25q = value of quarters in cents \n" ); document.write( ". \n" ); document.write( "The number of dimes is 4 less than 5 times the number of quarters. \n" ); document.write( "d = 5*q -4 \n" ); document.write( ". \n" ); document.write( "10d + 25q = 185 cents \n" ); document.write( ". \n" ); document.write( "Substitute \n" ); document.write( ". \n" ); document.write( "10*(5q-4) + 25q = 185 \n" ); document.write( ". \n" ); document.write( "50q -40 +25q = 185 \n" ); document.write( ". \n" ); document.write( "75q = 225 \n" ); document.write( ". \n" ); document.write( "q = 3 \n" ); document.write( ". \n" ); document.write( "d = 5*3-4 = 11 \n" ); document.write( ". \n" ); document.write( "Check the values. \n" ); document.write( "25*3 = 75 cents \n" ); document.write( "11*10 = 110 cents \n" ); document.write( "75+110 = 185 cents \n" ); document.write( "Correct. \n" ); document.write( ". \n" ); document.write( "Answer: 3 quarters and 11 dimes. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |