document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=551060>Question 551060</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist wants to make a 10% solution of fertilizer.  How much water and how much of a 30% solution should the chemist mix to get 30L of a 10% solution?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359338 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359338\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The key consideration with mixture problems is how much 'pure' stuff you need.<BR>\n" );
document.write( "The chemist wants 30 liters of a 10% solution:  30 * .1 = 3 liters of pure fertilizer and 27 liters of water.<BR>\n" );
document.write( "He has 30% solution on hand.<BR>\n" );
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document.write( "x = liters of 30% solution<BR>\n" );
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document.write( "30-x = liters of water to add, which is 0% pure fertilizer<BR>\n" );
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document.write( ".3*x + 0*(30-x) = .1*30<BR>\n" );
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document.write( ".3x = 3<BR>\n" );
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document.write( "x = 10 liters of 30% solution<BR>\n" );
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document.write( "30-x = 20 liters of pure water<BR>\n" );
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document.write( "Done. </SPAN>\n" );
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