document.write( "Question 551049: A goat is tied to one of the corners of a rectangular barn on a rope that is 50 feet long. The dimensions of the barn are 40 feet by 30 feet. Assuming that the goat can graze wherever its rope allows it to reach, what is the square footage of the grazing area for the goat? \n" ); document.write( "

Algebra.Com's Answer #359324 by AnlytcPhil(1806) $\"\"$ $\"About$

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document.write( "A goat is tied to one of the corners of a rectangular barn on a rope that is 50\r\n" );
document.write( "feet long.  The dimensions of the barn are 40 feet by 30 feet.  Assuming that\r\n" );
document.write( "the goat can graze wherever its rope allows it to reach, what is the square\r\n" );
document.write( "footage of the grazing area for the goat?\r\n" );
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document.write( "The area of a circle is pr²\r\n" );
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document.write( "The grazing area consists of \r\n" );
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document.write( "1. three quarters of a big 50ft-radius circle, which has area\r\n" );
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document.write( "    ·p(50)² = ·2500p square feet = 1875p square feet. \r\n" );
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document.write( "2. one quarter of a 20ft-radius circle on the left, which has area\r\n" );
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document.write( "    ·p(20)² = ·400p square feet = 100p square feet \r\n" );
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document.write( "3. one quarter of a small 10ft-radius circle on the top, which has area\r\n" );
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document.write( "    ·p(10)² = ·100p square feet = 25p square feet.  \r\n" );
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document.write( "Total = 1875p + 100p + 25p = 2000p square feet of grazing area.\r\n" );
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document.write( "Edwin McCravy aka AnlytcPhil

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