document.write( "Question 550973: A town is organizing a parade. There will be 2 float sizes. One is 30ft and the other is 15ft. A 10 ft space will be left after each float. \r
\n" ); document.write( "\n" ); document.write( "A.The parade must be a least 150ft long, but less than 200ft long. What combinations of large and small floats are possible?\r
\n" ); document.write( "\n" ); document.write( "B. Large float costs $600 to operate. Small floats cost $300 to operate. The town has a budget of $2500 to operate the floats. How does this change your answers to part A? What combinations of large and small floats are possible?
\n" ); document.write( "

Algebra.Com's Answer #359305 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
your cost equation is:
\n" ); document.write( "c = 600x + 300y
\n" ); document.write( "your cost has to be less than or equal to 2500, so your cost constraint becomes:
\n" ); document.write( "600x + 300y <= 2500
\n" ); document.write( "anything that costs over 2500 is rejected.
\n" ); document.write( "x = number of large floats
\n" ); document.write( "y = number of small floats
\n" ); document.write( "the formula for the maximum number of large floats is:
\n" ); document.write( "40x - 10 <= 200
\n" ); document.write( "this becomes 40x <= 210 which becomes:
\n" ); document.write( "x <= 210/40
\n" ); document.write( "this means that x has to be <= 5.25 which means that x has to be <= 5 since x has to be an integer.
\n" ); document.write( "the formula for the maximum number of small floats is:
\n" ); document.write( "25y - 10 <= 200
\n" ); document.write( "this becomes 25x <= 210 which becomes:
\n" ); document.write( "y <= 210/25
\n" ); document.write( "this means that y has to be <= 8.4 which means that y has to be <= 8 since y has to be an integer.
\n" ); document.write( "so far the constraints are:
\n" ); document.write( "x <= 5
\n" ); document.write( "y <= 8
\n" ); document.write( "the formula for the minimum number of floats in the parade is:
\n" ); document.write( "40x + 25y - 10 >= 150
\n" ); document.write( "add 10 to each side of this equation to get:
\n" ); document.write( "40x + 25y >= 160
\n" ); document.write( "the formula for the maximum number of floats in the parade is:
\n" ); document.write( "40x + 25y - 10 <= 200
\n" ); document.write( "add 10 to each side of this equation to get:
\n" ); document.write( "40x + 25y <= 210
\n" ); document.write( "the cost equation for this problem is:
\n" ); document.write( "600x + 300y <= 2500
\n" ); document.write( "this equation is both a constraint and the objective function of this problem.
\n" ); document.write( "we want the minimum cost and the cost has to be less than or equal to 2500.
\n" ); document.write( "we solve this equation graphically by doing the following:
\n" ); document.write( "graph the equation of y = 8
\n" ); document.write( "graph the equation of x = 5
\n" ); document.write( "graph the equation of 40x + 25y <= 210
\n" ); document.write( "graph the equation of 40x + 25y >= 160
\n" ); document.write( "graph the equation of 600x + 300y <= 2500
\n" ); document.write( "your graph will look something like the following:
\n" ); document.write( "
\n" ); document.write( "your area of compatibility will be below the graph of 600x + 300y = 2500 and above the graph of 40x + 25y = 160.
\n" ); document.write( "that area is shown in the following diagram.
\n" ); document.write( "\"$$$$$\"
\n" ); document.write( "it is within this region that all constraints are met.
\n" ); document.write( "all combinations within that region will have a parade length greater than or equal to 150 feet and less than or equal to 200 feet and will come within the maximum cost of 2500.
\n" ); document.write( "based on the properties of linear programming, the minimum / maximum points of the objective function are at the corners of the compatible region.
\n" ); document.write( "in this graph, those corners would be (x,y) coordinate points of:
\n" ); document.write( "(4,0)
\n" ); document.write( "(0,7)
\n" ); document.write( "(0,8)
\n" ); document.write( "while (7,0) and (8,0) are technically not at the corners, they are the nearest integers to those corners and one of the requirements are that x and y are integers.
\n" ); document.write( "when x = 4, the number of floats in the parade are 4 large and 0 small and the total cost is 600 * 4 = 2400 which is under the limit and the total number of feet required is 4*40 - 10 = 150 which is within the limits of 150 t 200 feet.
\n" ); document.write( "when y = 7, the number of floats in the parade are 0 large and 7 small and the total cost is 300 * 7 = 2100 which is under the limit and the total number of feet required is 7*25 - 10 = 165 which is within the limits of 150 to 200 feet.
\n" ); document.write( "when y = 8, the number of floats in the parade are 0 large and 8 small and the total cost is 300 * 8 = 2400 which is under the limit and the total number of feet required is 8* 25 - 10 = 190 feet which is within the limits of 150 to 200 feet.
\n" ); document.write( "the minimum cost combination is 0 large floats and 7 small floats.
\n" ); document.write( "there are other possible combinations that will be within the compatibility region.
\n" ); document.write( "those possible combinations are shown in the following table:
\n" ); document.write( "
\r\n" );
document.write( "large floats       small floats      feet required      cost\r\n" );
document.write( "0                      7                  165            2100\r\n" );
document.write( "0                      8                  190            2400\r\n" );
document.write( "1                      5                  155            2100\r\n" );
document.write( "1                      6                  180            2400\r\n" );
document.write( "2                      4                  170            2400\r\n" );
document.write( "3                      2                  160            2400\r\n" );
document.write( "4                      0                  150            2400\r\n" );
document.write( "

\n" ); document.write( "the minimum cost is at (0,7).
\n" ); document.write( "it is also at (1,5).
\n" ); document.write( "this stands to reason since 1*600 = 2*300 so you can exchange 1 large float for 2 small floats from a cost perspective and break even.
\n" ); document.write( "the fact that (1,5) is also a minimal cost does not negate the fact that the minimum or maximum value will be at the corners.
\n" ); document.write( "it still is, even though a value not at a corner is also a minimal cost.
\n" ); document.write( "
\n" ); document.write( "
\n" );