document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=550990>Question 550990</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Which pays more over the course of 10 days - $100 per day for the 10 days or one dollar the first day, $2.00 the second, $4.00 the third, $8.00 the fourth, etc., up to and including the 10th day?\r<BR>\n" );
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document.write( "Please help me solve this problem from my text book and show steps please. Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359272 by </B><A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><B>TutorDelphia(193)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=TutorDelphia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359272\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> $100 per day for 10 days will just be $100*10=$1000\r<BR>\n" );
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document.write( "The next one is a bit harder. To write its equation we would have to do summation notation (the sum of 1*2^(n-1) as n goes from 1 to 10), but to do it simply, we can just figure out the 10 days and sum them<BR>\n" );
document.write( "We are doubling each day.<BR>\n" );
document.write( "so we have 1+2+4+8+16+32+64+128+256+512=1023\r<BR>\n" );
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document.write( "So doubling pays more </SPAN>\n" );
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