document.write( "Question 550974: the length of a rectangle is 7 meters more than 4 times its width. the perimeter is 146 meters. find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #359267 by Maths68(1474)\"\" \"About 
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Length = l=4w+7 meters
\n" ); document.write( "Width = w=?
\n" ); document.write( "Perimeter = p = 146 meters\r
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\n" ); document.write( "\n" ); document.write( "Perimeter of a Rectangle = length + length + width + width
\n" ); document.write( "Perimeter of a Rectangle =2 length +2 width
\n" ); document.write( "P = 2l +2w
\n" ); document.write( "146=2(4w+7)+2w
\n" ); document.write( "146=8w+14+2w
\n" ); document.write( "146=10w+14
\n" ); document.write( "146-14=10w
\n" ); document.write( "132=10w
\n" ); document.write( "132/10=10w/10
\n" ); document.write( "13.2=w
\n" ); document.write( "w=13.2 meters\r
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\n" ); document.write( "\n" ); document.write( "Dimension of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "Length = l=4w+7 = 4(13.2)+7 = 52.8+7 = 59.8 meters
\n" ); document.write( "Width = w=13.2 meters
\n" ); document.write( "Perimeter = p = 146 meters
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