document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=550967>Question 550967</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a group of 5 cards is numbered 1-5 you choose one card at random. find each theoretical probability?\r<BR>\n" );
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document.write( "part a<BR>\n" );
document.write( "P(even number)\r<BR>\n" );
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document.write( "part b<BR>\n" );
document.write( "P(Prime Number)\r<BR>\n" );
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document.write( "part c<BR>\n" );
document.write( "P(less than 5)\r<BR>\n" );
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document.write( "part d<BR>\n" );
document.write( "P(card is 2)\r<BR>\n" );
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document.write( "thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359266 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359266\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Probability is desired/total.  There are 5 total cards, so that's the denominator.<P><BR>\n" );
document.write( "Even number - there are 2 even numbers so P(even) = 2/5 = 40%.<BR>\n" );
document.write( "Prime number - there are 3 prime numbers (2, 3, 5) so P(prime) = 3/5 = 60%.<BR>\n" );
document.write( "Less than 5 - there are 4 less than 5 (1, 2, 3, 4) so P(less than 5) = 4/5=80%.<BR>\n" );
document.write( "2 - there is one 2 so P(2) = 1/5=20%.<BR>\n" );
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document.write( "fcabanski@hotmail.com</B><P> </SPAN>\n" );
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