document.write( "Question 550932: A concert sells out a 20,000 seat arena. Main seat tickets cost $55, and back seat tickets for $45. The concert made $955,000. How many main seat tickets and back seat tickets were sold? \n" ); document.write( "
Algebra.Com's Answer #359245 by TutorDelphia(193)![]() ![]() You can put this solution on YOUR website! We know the total seats which are made up of main and back seats equals 20,000: \n" ); document.write( "m+b=20,000\r \n" ); document.write( "\n" ); document.write( "We know the earnings were 55 for every main and 45 for every back: \n" ); document.write( "55*m+45*b=955,000\r \n" ); document.write( "\n" ); document.write( "We now have a system of equations to solve. Lets multiply both sides of the first equation by 45\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now subtract : \n" ); document.write( "45m+45b=900,000 from \n" ); document.write( "55*m+45*b=955,000\r \n" ); document.write( "\n" ); document.write( "That gives us \n" ); document.write( "10m=55,000 \n" ); document.write( "so \n" ); document.write( "m=5,500 \n" ); document.write( "And if we sub m back into our first equation we find that \n" ); document.write( "b=14,500 \n" ); document.write( " |