document.write( "Question 550932: A concert sells out a 20,000 seat arena. Main seat tickets cost $55, and back seat tickets for $45. The concert made $955,000. How many main seat tickets and back seat tickets were sold? \n" ); document.write( "
Algebra.Com's Answer #359245 by TutorDelphia(193)\"\" \"About 
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We know the total seats which are made up of main and back seats equals 20,000:
\n" ); document.write( "m+b=20,000\r
\n" ); document.write( "\n" ); document.write( "We know the earnings were 55 for every main and 45 for every back:
\n" ); document.write( "55*m+45*b=955,000\r
\n" ); document.write( "\n" ); document.write( "We now have a system of equations to solve. Lets multiply both sides of the first equation by 45\r
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\n" ); document.write( "\n" ); document.write( "Now subtract :
\n" ); document.write( "45m+45b=900,000 from
\n" ); document.write( "55*m+45*b=955,000\r
\n" ); document.write( "\n" ); document.write( "That gives us
\n" ); document.write( "10m=55,000
\n" ); document.write( "so
\n" ); document.write( "m=5,500
\n" ); document.write( "And if we sub m back into our first equation we find that
\n" ); document.write( "b=14,500
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