document.write( "Question 550906: I need the derivative of : y = 1 / log x \r
\n" ); document.write( "\n" ); document.write( "The answer is supposed to be y' = -ln 10 / x(ln x) ^2 \r
\n" ); document.write( "\n" ); document.write( "I want to know how to do this.
\n" ); document.write( "Is there a solver on algebra.com to do this?
\n" ); document.write( "Thank you \n" ); document.write( "
Algebra.Com's Answer #359237 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "y = \"1%2Flog%28%28x%29%29\"\r\n" );
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document.write( "Use the change of base formula:\r\n" );
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document.write( "Y = \"1%2F%28ln%28x%29%2Fln%2810%29%29\"\r\n" );
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document.write( "Write as a division:\r\n" );
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document.write( "y = 1÷\"ln%28x%29%2Fln%2810%29\"\r\n" );
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document.write( "Invert and multiply:\r\n" );
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document.write( "y = 1·\"ln%2810%29%2Fln%28x%29\"\r\n" );
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document.write( "y = \"ln%2810%29%2Fln%28x%29\"\r\n" );
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document.write( "Bring the denominator to the numerator with a -1 power \r\n" );
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document.write( "y = ln(10)·[ln(x)]-1\r\n" );
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document.write( "                       Now we need two formulas \r\n" );
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document.write( "                       1) \"expr%28d%2Fdx%29\"\"%28u%5En%29\" = \"n%2Au%5E%28n-1%29expr%28%28du%29%2F%28dx%29%29\"\r\n" );
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document.write( "                       and\r\n" );
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document.write( "                       2) \"expr%28d%2Fdx%29\"\"ln%28u%29\" = \"1%2Fu\"·\"%28du%29%2F%28dx%29\"\r\n" );
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document.write( "y = ln(10)·[ln(x)]-1\r\n" );
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document.write( "\"dy%2Fdx\" = -1·ln(10)·[ln(x)]-2\"%281%2Fx%29\"\r\n" );
document.write( "\"dy%2Fdx\" = -ln(10)·\"1%2F%28%22ln_x%22%29%5E2\"\"%281%2Fx%29\"\r\n" );
document.write( "\"dy%2Fdx\" = -\"ln%2810%29%2F%28x%2A%28%22ln_x%22%29%5E2%29\"\r\n" );
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document.write( "Edwin
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