document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=550759>Question 550759</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A change purse contains a total of 100 nickels and dimes. The total value of the coins is $7. How many coins of each type does the purse contain? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359189 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359189\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A change purse contains a total of 100 nickels and dimes. The total value of the coins is $7. How many coins of each type does the purse contain?<BR>\n" );
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document.write( "Let n = the number of nickels<BR>\n" );
document.write( "Then 100 - n = the number of dimes<BR>\n" );
document.write( "We can write the following expression for the total value:<BR>\n" );
document.write( "5n + 10(100-n) = 700<BR>\n" );
document.write( "solve for n:<BR>\n" );
document.write( "5n + 1000 - 10n = 700<BR>\n" );
document.write( "5n = 300<BR>\n" );
document.write( "n = 60<BR>\n" );
document.write( "So the number of nickels is 60, the number of dimes is 40 </SPAN>\n" );
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