document.write( "Question 550872: The value of a certain two digit number is 9 times the sum of it's digits. If the digits are reversed, the resulting number is 63 less than the original number. What is the original number? Please, please help me answer this question! \n" ); document.write( "

Algebra.Com's Answer #359157 by stanbon(75887) $\"\"$ $\"About$

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The value of a certain two digit number is 9 times the sum of it's digits. If the digits are reversed, the resulting number is 63 less than the original number.
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\n" ); document.write( "Let the number be 10t+u.
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\n" ); document.write( "Equations:
\n" ); document.write( "10t+u = 9(t+u)
\n" ); document.write( "10u+t = 10t+u-63
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\n" ); document.write( "Simplify each equation:
\n" ); document.write( "t = 8u
\n" ); document.write( "9t = 9u + 63
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\n" ); document.write( "Modify:
\n" ); document.write( "t = 8u
\n" ); document.write( "t = u + 7
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\n" ); document.write( "Solve for \"u\":
\n" ); document.write( "8u = u+7
\n" ); document.write( "u = 1
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\n" ); document.write( "Solve for \"t\":
\n" ); document.write( "t = 8u
\n" ); document.write( "t = 8
\n" ); document.write( "---
\n" ); document.write( "Original Number: 10t+u = 81
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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