document.write( "Question 53661: find the linear depreciation equation for the TV in the advertisement shown below:\r
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document.write( "Three (3) years old flat screen TV;
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document.write( "Matrix surround sound with PIP remote
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document.write( "Bought new-$7,500.00; Asking $2,500.00 \n" );
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Algebra.Com's Answer #35915 by AnlytcPhil(1810) You can put this solution on YOUR website! find the linear depreciation equation for the TV in the \r\n" ); document.write( "advertisement shown below: \r\n" ); document.write( "Three (3) years old flat screen TV;\r\n" ); document.write( "Matrix surround sound with PIP remote\r\n" ); document.write( "Bought new-$7,500.00; Asking $2,500.00\r\n" ); document.write( "\r\n" ); document.write( "----------------------------------------\r\n" ); document.write( "\r\n" ); document.write( "When it was bought new, the time was = 0 years and the \r\n" ); document.write( "value was $7500.\r\n" ); document.write( "\r\n" ); document.write( "Now that it is being sold, the time is = 3 and the value \r\n" ); document.write( "is $2500.\r\n" ); document.write( "\r\n" ); document.write( "This amounts to finding the equation of a line that \r\n" ); document.write( "passes through the two points (0, 7500) and (3, 2500), \r\n" ); document.write( "where x represents the time and y represents the value of \r\n" ); document.write( "the TV.\r\n" ); document.write( "\r\n" ); document.write( " y2 - y1\r\n" ); document.write( "m = --------- \r\n" ); document.write( " x2 - x1\r\n" ); document.write( "\r\n" ); document.write( "where (x1,y1) = (0,7500) and (x2,y2) = (3,2500)\r\n" ); document.write( "\r\n" ); document.write( " 2500 - 7500 -5000\r\n" ); document.write( "m = ------------- = -------\r\n" ); document.write( " 3 - 0 3\r\n" ); document.write( "\r\n" ); document.write( "Now use the point-slope formula:\r\n" ); document.write( "\r\n" ); document.write( " y - y1 = m(x - x1)\r\n" ); document.write( "\r\n" ); document.write( "y - 7500 = -5000/3(x - 0)\r\n" ); document.write( "\r\n" ); document.write( "y - 7500 = (-5000/3)x\r\n" ); document.write( "\r\n" ); document.write( " y = 7500 - (5000/3)x\r\n" ); document.write( "\r\n" ); document.write( "We now would probably change y to V for value, and\r\n" ); document.write( "x to t for time\r\n" ); document.write( "\r\n" ); document.write( " V = 7500 - (5000/3)t where 0 < t < 4.5 \r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |