document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=550844>Question 550844</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The points A(-1,2),B(x,y) and C=(4,5) are such that BA=BC.Find a linear relation between x and y. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359148 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359148\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> point B will be any point on the perpendicular bisector of AC.<BR>\n" );
document.write( "as such it will be equidistant between A and C which will always make AB = BC.<BR>\n" );
document.write( "the linear relationship is the equation of the line that passes through the midpoint of AC and is perpendicular to it.<BR>\n" );
document.write( "the equation of the line AC is:<BR>\n" );
document.write( "y = (3/5)x + (13/5)<BR>\n" );
document.write( "the equation of the line perpendicular to AC and passing through its midpoint is:<BR>\n" );
document.write( "y = -(5/3)x + 6<BR>\n" );
document.write( "the graph of the equations for those line is shown below:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28600%2C600%2C-15%2C15%2C-15%2C15%2C%283%2F5%29x+%2B+%2813%2F5%29%2C-%285%2F3%29x%2B6%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "point B is any point on the line perpendicular to AC, so the linear relationship between the x value of that point and the y value of that point is the equation of the line perpendicular to AC which is the equation:<BR>\n" );
document.write( "y = -(5/3)x + 6.<BR>\n" );
document.write( "a picture of the relationship is shown below:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2011/dec291.jpg\" alt = \"$$$$$\" /><BR>\n" );
document.write( "line DE is perpendiculat to line AC.<BR>\n" );
document.write( "any point on line DE is equidistant from A and C.<BR>\n" );
document.write( " </SPAN>\n" );
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