document.write( "Question 550800: 1.What point on x-axis is equidistance from the points(6,7) and (4,-3)?
\n" ); document.write( "2.Find the equations of the diagonals of a rectangle whose sides are x+1=0,x-4=0,y+1=0 and y-2=0.
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Algebra.Com's Answer #359106 by mananth(16949)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "let Q be the point on the x axis (x,0)
\n" ); document.write( "Let P be (6,7)
\n" ); document.write( "distance PQ\r
\n" ); document.write( "\n" ); document.write( "d^2=((7-0)^2+(6-x)^2
\n" ); document.write( "d^2=49+36-12x+x^2
\n" ); document.write( "d^2=85-12x+x^2\r
\n" ); document.write( "\n" ); document.write( "Let the second point be R (4,-3)
\n" ); document.write( "Distance RQ=\r
\n" ); document.write( "\n" ); document.write( "d^2=(-3-0)^2+(4-x)^2
\n" ); document.write( "d^2=9+16-8x+x^2
\n" ); document.write( "D(RQ)=d(PQ)
\n" ); document.write( "square
\n" ); document.write( "85-12x+x^2=9+16-8x+x^2
\n" ); document.write( "60=4x
\n" ); document.write( "x=15
\n" ); document.write( "point Q(15,0)
\n" ); document.write( "CHECK\r
\n" ); document.write( "\n" ); document.write( "d^2(RQ)=(-3-0)^2+(4-15)^2
\n" ); document.write( "d^2(RQ)=9+121=130\r
\n" ); document.write( "\n" ); document.write( "d^2(PQ)=49+81=130\r
\n" ); document.write( "\n" ); document.write( "---------------
\n" ); document.write( "2.Find the equations of the diagonals of a rectangle whose sides are x+1=0,x-4=0,y+1=0 and y-2=0.\r
\n" ); document.write( "\n" ); document.write( "the lines are x=-1, y=-1, x=4, y=2\r
\n" ); document.write( "\n" ); document.write( "intersection points of the lines are
\n" ); document.write( "(-1,-1),(-1,2),(4,2),(4,-1)
\n" ); document.write( "Calculate the slope of the line passing through the points on the diagoinal
\n" ); document.write( "(-1,-1) & (4,2)\r
\n" ); document.write( "\n" ); document.write( "x1 y1 x2 y2
\n" ); document.write( "-1 -1 4 2
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\n" ); document.write( "slope m = (y2-y1)/(x2-x1)
\n" ); document.write( "( 2 - -1 )/( 4 - -1 )
\n" ); document.write( "( 3 / 5 )
\n" ); document.write( "m= 3/ 5
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\n" ); document.write( "Plug value of the slope and point ( -1 , -1 ) in
\n" ); document.write( "Y = m x + b
\n" ); document.write( "-1.00 = - 3/5 + b
\n" ); document.write( "b= -1 - - 3/5
\n" ); document.write( "b= - 2/ 5
\n" ); document.write( "So the equation will be
\n" ); document.write( "Y = 3/5 x - 2/5
\n" ); document.write( "m.ananth@hotmail.ca \r
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