document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=550797>Question 550797</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Divide Rs 1,870 into three parts in such a way that half of the first part,one-third of the second part and one-sixth of the third part are equal. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359103 by </B><A HREF=/tutors/aboutme.mpl?userid=mathstutor494><B>mathstutor494(120)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathstutor494><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mathstutor494><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359103\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let equal part be \"x\"\r<BR>\n" );
document.write( "\n" );
document.write( "> first part = 2x<BR>\n" );
document.write( "> second part = 3x<BR>\n" );
document.write( "> third part  = 6x\r<BR>\n" );
document.write( "\n" );
document.write( "As sum total of all parts = 1870\r<BR>\n" );
document.write( "\n" );
document.write( "Therefore 2x+3x+6x = 1870\r<BR>\n" );
document.write( "\n" );
document.write( "> 11x = 1870\r<BR>\n" );
document.write( "\n" );
document.write( "So x = 1870/11 > 170 Ans </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );