document.write( "Question 550730: The total cost of a taxi ride is the sum of
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document.write( "a) A basic fixed cost for the first five miles
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document.write( "b) An additional charge for every three miles after the first five.\r
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document.write( "If the cost to travel 11 miles is $5, and the cost to travel 35 miles is $11, how many miles can you go with $7.25?\r
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document.write( "Please explain step by step, thanks. \n" );
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Algebra.Com's Answer #359027 by TutorDelphia(193) You can put this solution on YOUR website! The total cost of a taxi ride is the sum of \n" ); document.write( "a) A basic fixed cost for the first five miles which we will call b \n" ); document.write( "b) An additional charge for every three miles after the first five which we will call a\r \n" ); document.write( "\n" ); document.write( "Lets make mileage be m\r \n" ); document.write( "\n" ); document.write( "In order to figure out the millage after the first 5 we can just do m-5.\r \n" ); document.write( "\n" ); document.write( "But the charge is for every three miles so we have to do (m-5)/3\r \n" ); document.write( "\n" ); document.write( "Our formula will be b+a*((m-5)/3)\r \n" ); document.write( "\n" ); document.write( "If the cost to travel 11 miles is $5, and the cost to travel 35 miles is $11, how many miles can you go with $7.25? \n" ); document.write( "For 11 miles (which cost 5 dollars) \n" ); document.write( "5=b+a*((11-5)/3)\r \n" ); document.write( "\n" ); document.write( "5=b+a*2 \n" ); document.write( "For 35 miles (which cost 11 dollars) \n" ); document.write( "11=b+a*((35-5)/3) \n" ); document.write( "11=b+a*10\r \n" ); document.write( "\n" ); document.write( "Now we can use elimination method:\r \n" ); document.write( "\n" ); document.write( "11=b+a*10 \n" ); document.write( "minus \n" ); document.write( "5=b+a*2 \n" ); document.write( "6=a*8 \n" ); document.write( "a=6/8=3/4\r \n" ); document.write( "\n" ); document.write( "now lets sub in for a \n" ); document.write( "5=b+a*2 \n" ); document.write( "5=b+(3/4)*2 \n" ); document.write( "5=b+3/2 \n" ); document.write( "5=b+1.5 \n" ); document.write( "b=3.5\r \n" ); document.write( "\n" ); document.write( "So our formula is now c=3.50+(3/4)*((m-5)/3)\r \n" ); document.write( "\n" ); document.write( "So let's see how far we can go for 7.25\r \n" ); document.write( "\n" ); document.write( "7.25=3.50+(3/4)*((m-5)/3) \n" ); document.write( "3.75=(3/4)*((m-5)/3)=1/4*(m-5) (because the divided by 3 and the 3 in the numerator cancel out) \n" ); document.write( "3.75=1/4*(m-5) \n" ); document.write( "3.75*4=m-5 \n" ); document.write( "15=m-5 \n" ); document.write( "m=20 \n" ); document.write( " |