document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=53647>Question 53647</A>: <I><SPAN STYLE=\"word-break: break-all;\"> determine the equation of the line passing through the point (-2,3) and perpendicular to the graph of x+y=24 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #35899 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=35899\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> determine the equation of the line passing through the point (-2,3) and perpendicular to the graph of x+y=24<BR>\n" );
document.write( "ANY PERPENDICULAR TO GIVEN LINE IS<BR>\n" );
document.write( " X-Y = K..........IT PASSES THROUGH (-2,3)<BR>\n" );
document.write( "HENCE <BR>\n" );
document.write( "-2-3=K=-5<BR>\n" );
document.write( "HENCE REQD.EQN.IS <BR>\n" );
document.write( "X-Y=-5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );