document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=53648>Question 53648</A>: <I><SPAN STYLE=\"word-break: break-all;\"> PLEASE HELP ME SOLVE:\r<BR>\n" );
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document.write( "BOX HAS TOTAL OF 44 COINS, CONSISTING OF PENNIES, DIMES AND QUARTERS. THE NUMBER OF PENNIES IS EQUAL TO THE NUMBER OF DIMES, AND THE TOTAL VALUE IS $4.37 HOW MANY OF EACH DENOMINATION OF COIN DOES HE HAVE. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #35893 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=35893\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 44=2x+q & 4.37=.01x+.10x+.25q or q=44-2x or 4.37=.01x+.10x+.25(44-2x) or\r<BR>\n" );
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document.write( "4.37=.0x+.10x+11.00-.50x or 4.37-11.00=.01x+.10x-.50x or -6.63=-.39x or \r<BR>\n" );
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document.write( "6.63/.39=x or x=17 thus there are 17 pennies, 17 dimes & 10 quarters\r<BR>\n" );
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document.write( "proof 17+17=10=44 & .01*17+.10*17+.25*10=4.37 .17+1.70+2.50=4.37 or 4.37=4.37 </SPAN>\n" );
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