document.write( "Question 550591: A boat travels 60 miles downstream in The same time it takes to go 36 miles upstream. The speed of The boat in still water is 15 mph greater than The speed of The current. Find The speed of The current. \n" ); document.write( "
Algebra.Com's Answer #358902 by ankor@dixie-net.com(22740)\"\" \"About 
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A boat travels 60 miles downstream in The same time it takes to go 36 miles upstream.
\n" ); document.write( " The speed of The boat in still water is 15 mph greater than The speed of The current.
\n" ); document.write( " Find The speed of The current.
\n" ); document.write( ":
\n" ); document.write( "Let x = speed of the current
\n" ); document.write( "and
\n" ); document.write( "(x+15) = speed of the boat in still water
\n" ); document.write( "then
\n" ); document.write( "x + (x+15) = 2x+15; the effective speed down stream
\n" ); document.write( "and
\n" ); document.write( "(x+15) - x = 15 mph; the effective speed upstreams\r
\n" ); document.write( "\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "downstr time = upstr time
\n" ); document.write( "\"60%2F%28%282s%2B15%29%29\" = \"36%2F15\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "36(2s+15) = 60 * 15
\n" ); document.write( "72s + 540 = 900
\n" ); document.write( "72s = 900 - 540
\n" ); document.write( "72s = 360
\n" ); document.write( "s = \"360%2F72\"
\n" ); document.write( "s = 5 mph is the rate of the current
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this solution,
\n" ); document.write( "The speed of the boat in still water = 15 + 5 = 20 mph
\n" ); document.write( "The speed with the current: 20 + 5 = 25 mph
\n" ); document.write( "The speed against the current: 20 - 5 = 15 mph
\n" ); document.write( ":
\n" ); document.write( "Find the time each way, they should be equal
\n" ); document.write( "60/25 = 2.4 hrs
\n" ); document.write( "36/15 = 2.4
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