document.write( "Question 53642: Consider the linear equation represented by y=6x+12
\n" ); document.write( "i. Find the x-intercept of its graph
\n" ); document.write( "ii. Find the y-intercept of its graph
\n" ); document.write( "iii.Does its graph pass through the point(-1,6) \n" ); document.write( "

Algebra.Com's Answer #35890 by rchill(405) $\"\"$ $\"About$

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To find the y-intercept, substitute 0 in for x to get $\"y=12\"$ . Similarly, for the x-intercept, substitute 0 in for y to get $\"x=-2\"$ . You can look at the following graph to see if the line passes through (-1,6), but it's much easier to just substitute -1 for x into the equation to get $\"y=6\"$ . Therefore, the line does indeed pass through that point. Here's the graph: $\"graph%28300%2C300%2C-5%2C5%2C-2%2C15%2C6x%2B12%29\"$ \n" ); document.write( "

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