document.write( "Question 550527: Two hunters H1 and H2 shoot at a wolf. 0.34 is the probability that H1 will kill a wolf by one shot and 0.51 is the probability that H2 will kill a wolf by one shot, 2 is the number of shots performed by H1 and 3 is the number of shots performed by H2. Find the probability that after 5 shots the wolf is not killed. \n" ); document.write( "
Algebra.Com's Answer #358871 by TutorDelphia(193) You can put this solution on YOUR website! If .34 is the probability H1 will kill it, than 1-.34=.66 is the probability he won't. Same goes for H2 which will be .49\r \n" ); document.write( "\n" ); document.write( "So we have \n" ); document.write( ".66*.66*.66 *.49*.49=.069\r \n" ); document.write( "\n" ); document.write( "Poor woof. \n" ); document.write( " |