document.write( "Question 550577: How many liters of 20% alcohol solution should be added to 40 liters of a 50% alcohol solution to make a 30% solution? \n" ); document.write( "
Algebra.Com's Answer #358869 by mathstutor494(120)\"\" \"About 
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Let quantity of 20% alcohol solution be added : x liters\r
\n" ); document.write( "\n" ); document.write( "Eqn for altered solution ....\r
\n" ); document.write( "\n" ); document.write( "> x*20% + 40 * 50% = (x+40) * 30%\r
\n" ); document.write( "\n" ); document.write( "> x*0.2 + 40*0.5 = (x+40)*0.3 ..(converting percentages into decimal)
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\n" ); document.write( "> 0.2x + 20 = 0.3x + 12
\n" ); document.write( "> 20-12 = 0.3x - 0.2x (Rearranging similar terms)
\n" ); document.write( "> 8 = 0.1 x
\n" ); document.write( "Hence x = 8/0.1
\n" ); document.write( "Ans 80 Litres\r
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