document.write( "Question 550577: How many liters of 20% alcohol solution should be added to 40 liters of a 50% alcohol solution to make a 30% solution? \n" ); document.write( "

Algebra.Com's Answer #358863 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = liters of 20% solution needed
\n" ); document.write( "given:
\n" ); document.write( " $\"+.5%2A40+=+20+\"$ liters of alcohol in 50% solution
\n" ); document.write( " $\"+.2x+\"$ liters of alcohol in 20% solution
\n" ); document.write( "-------------
\n" ); document.write( " $\"+%28+20+%2B+.2x+%29+%2F+%28+40+%2B+x+%29+=+.3+\"$
\n" ); document.write( " $\"+20+%2B+.2x+=+.3%2A%28+40+%2B+x+%29+\"$
\n" ); document.write( " $\"+20+%2B+.2x+=+12+%2B+.3x+\"$
\n" ); document.write( " $\"+.1x+=+20+-+12+\"$
\n" ); document.write( " $\"+.1x+=+8+\"$
\n" ); document.write( " $\"+x+=+80+\"$
\n" ); document.write( "80 liters of 20% solution are needed
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+20+%2B+.2x+%29+%2F+%28+40+%2B+x+%29+=+.3+\"$
\n" ); document.write( " $\"+%28+20+%2B+.2%2A80+%29+%2F+%28+40+%2B+80+%29+=+.3+\"$
\n" ); document.write( " $\"+%28+20+%2B+16+%29+%2F+120+=+.3+\"$
\n" ); document.write( " $\"+36+%2F+120+=+.3+\"$
\n" ); document.write( " $\"+36+=+.3%2A120+\"$
\n" ); document.write( " $\"+36+=+36+\"$
\n" ); document.write( "OK\r
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