document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=53621>Question 53621</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having a hard time figuring out this problem.\r<BR>\n" );
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document.write( "Use the geometric sequence of numbers 1, 1/2, 1/4, 1/8,…to find the following:<BR>\n" );
document.write( "a) 	What is r, the ratio between 2 consecutive terms? \r<BR>\n" );
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document.write( "b) 	Using the formula for the sum of the first n terms of a geometric series, what is the sum of the first 10 terms? Please round your answer to 4 decimals.<BR>\n" );
document.write( "c) 	Using the formula for the sum of the first n terms of a geometric series, what is the sum of the first 12 terms? Please round your answer to 4 decimals.\r<BR>\n" );
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document.write( "Thanks for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #35872 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=35872\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the geometric sequence of numbers 1, 1/2, 1/4, 1/8,…to find the following:<BR>\n" );
document.write( "a) What is r, the ratio between 2 consecutive terms? <BR>\n" );
document.write( "r=(1/2)/1= 1/2<BR>\n" );
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document.write( "b) Using the formula for the sum of the first n terms of a geometric series, what is the sum of the first 10 terms? Please round your answer to 4 decimals.<BR>\n" );
document.write( "S(n)=a[(r^(n+1)-1)/(r-1)]<BR>\n" );
document.write( "S(10)=1[(1/2)^11 -1)/((1/2)-1]<BR>\n" );
document.write( "S(10)=(1/2048 - 1)/(-1/2)<BR>\n" );
document.write( "S(10)=1.9990<BR>\n" );
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document.write( "c) Using the formula for the sum of the first n terms of a geometric series, what is the sum of the first 12 terms? Please round your answer to 4 decimals.<BR>\n" );
document.write( "Same procedure as part \"b\" but use n=12<BR>\n" );
document.write( "Answer should be 1.9999<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
document.write( " </SPAN>\n" );
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