document.write( "Question 550387: 6500 us were divided equally among a certain number of persons. had there been 15 more persons, each would have got 30 us less. find the original number of persons. \n" ); document.write( "
Algebra.Com's Answer #358689 by JBarnum(2146)\"\" \"About 
You can put this solution on YOUR website!
i dont know what a (us) is other than my country..lol but i will just say they are dollars($)
\n" ); document.write( "p= persons , x= amount per person
\n" ); document.write( "\"6500=px\"
\n" ); document.write( "\"6500=%28p%2B15%29%28x-30%29\"
\n" ); document.write( "the equations above come straight from the problem, the more word problems you do the easier it will become to recognize the equations
\n" ); document.write( "\"6500%2Fp=x\"
\n" ); document.write( "use substitution methed\r
\n" ); document.write( "\n" ); document.write( "\"6500=%28p%2B15%29%28x-30%29\" foil
\n" ); document.write( "\"6500=%28px%2B15x-30p-450%29\" substitute x
\n" ); document.write( "\"6500=%28p%286500%2Fp%29%2B15%286500%2Fp%29-30p-450%29\"
\n" ); document.write( "\"6500=6500%2B97500%2Fp-30p-450\"add like terms
\n" ); document.write( "\"450=97500%2Fp-30p\" multiply by p
\n" ); document.write( "\"450p=97500-30p%5E2\" organize in ax^2+bx+c=0
\n" ); document.write( "\"30p%5E2%2B450p-97500=0\" take the 30 out
\n" ); document.write( "\"30%28p%5E2%2B15p-3250%29\" find 2 numbers that multiply to get -3250 and add to get +15
\n" ); document.write( "5*5*5*2*13=3250, 5*13=65 5*5*2=50, 65*-50=-3250 , 65-50=+15
\n" ); document.write( "\"30%28p%2B65%29%28p-50%29=0\"
\n" ); document.write( "\"p=-65\"\"p=50\" p cant be negative so answer is \"highlight%2850%29\"
\n" ); document.write( "\"6500%2Fp=x\"
\n" ); document.write( "\"6500%2F50=x\"
\n" ); document.write( "\"130=x\"
\n" ); document.write( "check
\n" ); document.write( "\"6500=%28p%2B15%29%28x-30%29\"
\n" ); document.write( "\"6500=%2850%2B15%29%28130-30%29\"
\n" ); document.write( "\"6500=%2865%29%28100%29\"
\n" ); document.write( "\"6500=6500\"
\n" ); document.write( "correct
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