document.write( "Question 550378: The ratio of the prices of two fans was 16:23.Two years later,when the price of the first fan had risen by 10% and that of the second by Rs 477,the ratio of their prices became 11:20.Find the original prices of two fans.
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Algebra.Com's Answer #358682 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Ratio of two fans = 16:23\r \n" ); document.write( "\n" ); document.write( "multiply by common factor x \n" ); document.write( "the prices will be 16x & 23x\r \n" ); document.write( "\n" ); document.write( "AFTER TWO YEARS\r \n" ); document.write( "\n" ); document.write( "first fan increaed by 10 % = 0.1*16x \n" ); document.write( "price of the fan =16x+1.6x= 17.6x\r \n" ); document.write( "\n" ); document.write( "increase in other fan = Rs. 477 \r \n" ); document.write( "\n" ); document.write( "price = 23x+477\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cross multiply \n" ); document.write( "352x=11(23x+477) \n" ); document.write( "352x=253x+5247\r \n" ); document.write( "\n" ); document.write( "352x-253x=5247 \n" ); document.write( "99x=5247 \n" ); document.write( "x=53\r \n" ); document.write( "\n" ); document.write( "Price of one fan = 53*16 =Rs. 848 \n" ); document.write( "price of second fan = Rs. 1219 \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |